Re: [Haskell-beginners] Monad operators: multiple parameters

On 04:30 Tue 07 Jun , Christopher Howard wrote:

In a reply to an earlier question, someone told me that "do" expressions are simply syntactic sugar that expand to expressions with the >> and

...

...

= operators. I was trying to understand this (and the Monad class) better.

I see in my own experiments that this...

main = do ln1 <- getLine putStrLn ln1

translates to this:

main = getLine >>= \ln1 -> putStrLn ln1

However, what does this translate to?:

main = do ln1 <- getLine ln2 <- getLine putStrLn (ln1 ++ ln2)

It translates to: main = getLine >>= \ln1 -> getLine >>= \ln2 -> putStrLn (ln1 ++ ln2) -- Mats Rauhala MasseR