[Haskell-beginners] Re: Sequential IO processing

Sergey V. Mikhanov wrote:

I tried this earlier as well:

sequenceIO [] = return [] sequenceIO (x : xs) = do result <- x resultTail <- sequenceIO xs return result : resultTail

The last line should be return (result : resultTail) otherwise it will be parsed as (return result) : resultTail which is not what you want. Regards, apfelmus -- http://apfelmus.nfshost.com