Re: [Haskell-beginners] Palindromic solution??

On 16 Feb 2009, at 19:30, Dave Bayer wrote:

Here's a solution harder on the machine, easier on the brain:

isPalindrome :: Eq a => [a] -> Bool isPalindrome xs = and $ zipWith (==) xs $ reverse xs

Lets just tidy that up a little... isPalindrome = (and . zipWith (==)) <*> reverse But I don't see how either is easier on the brain than xs == reverse xs. Bob