On Fri, Feb 6, 2015 at 6:25 PM, Roelof Wobben
Hello,
I have figured out how I can make from 123 [1,2,3]
I did it this way :
-- | convert a number to a array in pieces where a negative number will be a empty array. toDigits :: Integer -> [Integer] toDigits n | n <= 0 = [] | otherwise = toDigits (n `div` 10) ++ [n `mod` 10]
but now when I do toDigits 0 , I see [] as output where I was expected [0]
But when I do toDigits 100 I see the right output [ 1,0,0] which surprises me because I tought that with the first 0 there will be a []
Or is the n the second time [0,0] and the thirth time [0] So it will be like this :
toDigits 100
to Digits [1] ++ [ 0,0] toDigits [1] ++ [0] ++ [0]
which leads to [1,0,0]
toDigits 100 toDigits 10 ++ [0] toDigits 1 ++ [0] ++ [0] [1] ++ [0] ++ [0] [1,0,0] toDigits 0 [] -- because first guard clause 0 is valid input. It should be dealt different from negative number. -- YCH