Re: [Haskell-beginners] point-free + IO Monad

That's good enough. Thanks! On Sun, Mar 31, 2013 at 11:08 AM, Franco wrote:

Ovidiu D writes:

...

I have the following code:

f1 :: String -> String

f2 :: IO String -> IO () f2 a = do b <- a putStr $ f1 b

How can I write the function f2 in a point-free style?

maybe

f2 = (=<<) (putStrLn . f1)

I still prefer the non point-free but clearer

f2 = a >>= (putStrLn . f1)

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