Re: [Haskell-beginners] Re: Sequential IO processing

Now works! Thank you very much -- a nice lesson learned for me. S.

...

I tried this earlier as well:

sequenceIO [] = return [] sequenceIO (x : xs) = do result <- x resultTail <- sequenceIO xs return result : resultTail

The last line should be

return (result : resultTail)

otherwise it will be parsed as

(return result) : resultTail

which is not what you want.

Regards, apfelmus