16 May
2016
16 May
'16
10:25 a.m.
Correct, you're stuck always writing it with the parenthese because without
them; you get an infix function which is binary, not unary.
I still don't see what your solution brings new to the table in relevance
to the question. It's just trading a poorly named function for arguably an
even worse.
On May 16, 2016 10:20 AM, "Imants Cekusins"
Alex
here is what I tried:
(%%):: Applicative f => a -> f a (%%) = pure
test::Int -> IO Int test i0 = (%%) $ i0 + (2::Int)
seems to work..
I can't get %% to work without ()
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