Re: [Haskell-beginners] Function composition with more than 1 parameter

Glurk, "(.) . (.)" seems to do it: dorsey@elwood:~$ ghci GHCi, version 6.8.3: http://www.haskell.org/ghc/ :? for help Loading package base ... linking ... done. Prelude> let (...) = (.) . (.) Prelude> let matches x xs = [ m | m <- xs, x == m ] Prelude> :t length ... matches length ... matches :: (Eq a) => a -> [a] -> Int Prelude> Regards, John