Re: [Haskell-beginners] Trying to understand the foldl type?

On Tue, Dec 24, 2013 at 8:19 PM, Angus Comber wrote:

foldl :: (a -> b -> a) -> a -> [b] -> a

Eg I might do something like this:

foldl (+) 0 [1..10]

Try the following in ghci to see if you get an idea of what's going on: :t foldl :t foldl (+) :t foldl (+) 0 :t foldl (+) 0 [1..10] -- Kim-Ee