Re: [Haskell-beginners] rational exponents

On 09/07/2011 12:38 PM, Brandon Allbery wrote:

On Wed, Sep 7, 2011 at 16:25, Christopher Howard mailto:christopher.howard@frigidcode.com> wrote:

Hi. I'm working with simple functions involving rational exponents. I noticed that the (**) function seems to do okay with negative powers, but that something else is needed for rational exponents:

Nothing else is needed; you're just seeing the inevitable failure mode of floating point math (once you get into exponents that aren't integers, you can't escape it). You may want to restrict printing precision.

(No, this is not a bug. No, there is no workaround that magically makes floating point behave the way new users think it should. And no, this is absolutely *not* Haskell-specific; the same kind of question constantly comes up with C, C++, Perl, Java, PHP, ....)

-- brandon s allbery allbery.b@gmail.com mailto:allbery.b@gmail.com wandering unix systems administrator (available) (412) 475-9364 vm/sms

Are there any alternative approaches that could taken? Perhaps, some kind of Floating Ratio implementation? Prelude Data.Ratio> 8 ** (2 % 3) <interactive>:1:3: No instance for (Floating (Ratio a0)) arising from a use of `**' Possible fix: add an instance declaration for (Floating (Ratio a0)) In the expression: 8 ** (2 % 3) In an equation for `it': it = 8 ** (2 % 3) Or maybe an all-rational math? I'm mainly curious as my CASIO fx-115W calculator returns a result of exactly 4 if I input 8^(2/3), but I do not know how it arrives at the answer. -- frigidcode.com theologia.indicium.us