Re: [Haskell-beginners] Function result being inversed

f (<) 3 == (<) 4 3 == 4 < 3 == False On 25 January 2011 21:00, Xavier Shay wrote:

Hello, I am confused by the following code. I would expect results of True, False.

$ ghci *Main> let f x = x 4 *Main> f(<) 3 False *Main> f(<) 5 True

This came about because I was trying to refactor a sort function I wrote:

 mySort [] = []  mySort (h:t) =    (f (<= h)) ++ [h] ++ (f (> h))    where f x = mySort (filter x t)

I came up with this, which appears to work, though the comparison operators are backwards.

 mySort [] = []  mySort (h:t) =    f(>) ++ [h] ++ f(<=)    where f x = mySort (filter (x h) t)

Cheers, Xavier

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