
The difference is that one of them is:
— unnecessary parentheses for emphasis
(init tail) [1, 2, 3]
And the other is
— parentheses required for correct evaluation
init (tail [1, 2, 3])
On Tue, Jan 26, 2021 at 08:23 Lawrence Bottorff
:t (init tail) : error: : * Couldn't match expected type `[a]' : with actual type `[a0] -> [a0]' : * Probable cause: `tail' is applied to too few arguments : In the first argument of `init', namely `tail' : In the expression: (init tail)
:t (init . tail) : (init . tail) :: [a] -> [a]
:t init $ tail : error: * Couldn't match expected type `[a]' with actual type `[a0] -> [a0]' * Probable cause: `tail' is applied to too few arguments In the second argument of `($)', namely `tail' In the expression: init $ tail
chopEnds = init $ tail chopEnds [1,2,3] error: ... * Variable not in scope: chopEnds1 :: [Integer] -> t ...
but then
init $ tail [1,2,3] [2]
Not sure what I'm missing here. It doesn't make sense to me that the last expression works, but no version of a closure
chopEnds = init $ tail
does.
On Mon, Jan 25, 2021 at 7:58 PM Kim-Ee Yeoh
wrote: init $ tail [1,2,3] = init (tail ([1,2,3])) -- a la Lisp
Now, functional programming is awesomest at abstractions. What if we could abstract out "init (tail"?
Then we could write
chopEnds = init (tail
But that looks weird. It's only got the left half of a parens pair!
Does that explain why you should not expect the same result?
A separate question is why the compiler even type-checks "init $ tail" in the first place. What do you think is going on there?
On Tue, Jan 26, 2021 at 1:16 AM Lawrence Bottorff
wrote: I've got this
init $ tail [1,2,3] [2]
and this
chopEnds = init $ tail chopEnds [1,2,3] [1,2]
What happened? Why is it not just init $ tail [1,2,3] ?
This works fine
chopEnds2 = init . tail chopEnds2 [1,2,3] [2]
What am I missing?
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