Hi, Looking at the structure of the expression, you should have foldr operator accumulator list So in your example the accumulator should be "return" (because it is the second argument) Il gio 26 lug 2018, 03:45 Olumide <50295@web.de> ha scritto:
Dear List,
Chapter 13 of LYAH ( http://learnyouahaskell.com/for-a-few-monads-more#useful-monadic-functions)
has the following code block
import Data.List
inMany :: Int -> KnightPos -> [KnightPos] inMany x start = return start >>= foldr (<=<) return (replicate x oveKnight)
What I'd like to know is where the accumulator of foldr is in this example.
Regards,
- Olumide
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