Re: [Haskell-beginners] hide Perl code inside Haskell program

This way works fine if the program has no arguments. What if I have to pass arguments such as "-i input -o output"? Thanks, Hong On Thu, Sep 10, 2009 at 12:45 PM, José Prous wrote:

you are putting the perl script as the name of the command you can do something like: rawSystem "perl" ["-e","print \"testing ...\n\";" ] this is equivalent to call in the shell: perl -e "print \"testing ...\";" (sorry Hong I din't put reply to all in the fist mail) On Thu, Sep 10, 2009 at 1:24 PM, Hong Yang wrote:

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I was trying to hide Perl code inside Haskell program like the following:

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module Main where

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import System.Environment (getArgs) import System.Cmd

...

main = do args <- getArgs rawSystem pl args where pl = "#!/usr/bin/perl\n" ++ "print \"testing ...\n\";"

The program can run, but generates no output at all. Can someone tell me any other tricks which might be missing? (Do we need to use pipe here?)

Thanks,

Hong

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