12 Feb
2014
12 Feb
'14
10:03 p.m.
On Wed, Feb 12, 2014 at 8:05 PM, Bryan Brady <bryan.brady@gmail.com> wrote:
What solution do you think the author had in mind? He did hint to use define and use interleaveStreams and to avoid checking divisibility testing.
Recall the famous haskell fibonacci: fib = 0 : 1 : some_function_of fib Mathematically speaking, what fractal property does the ruler sequence observe that you could similarly exploit? As for your solution, I don't doubt for a minute it's correct (I probably could have worded what I said better). The hope is that a proof would be interesting/delightful in that ineffable math-y way. -- Kim-Ee