Re: [Haskell-beginners] oddsFrom3 function

You can also peruse SICP for knowing about how lazy evaluation works. The explanations are nice. It is in lisp, though. https://mitpress.mit.edu/sicp/full-text/book/book-Z-H-24.html#%_sec_3.5 On Mon, Aug 17, 2015 at 2:12 PM, akash g wrote:

Hi Rein,

The initial version which the OP posted doesn't have a terminal value. The OP had posted the version that he'd wanted clarification on.

On Mon, Aug 17, 2015 at 12:40 PM, Rein Henrichs wrote:

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It will absolutely work. Lists can be infinite in Haskell and infinite lists are productive:

λ> take 5 oddsFrom3 [3,5,7,9,11]

On Mon, Aug 17, 2015 at 12:05 AM Debdut Karmakar wrote:

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On 2015-08-17 02:35, akash g wrote:

Not a problem. And I should have thought about what you wanted too.

This version will give you an infinite list of odd numbers from 3.

On Mon, Aug 17, 2015 at 12:02 PM, Debdut Karmakar

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wrote:

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Sorry, I wrote a wrong function, the correct version is:

oddsFrom3 :: [Integer] oddsFrom3 = 3 : map (+2) oddsFrom3 --

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I know that it will evaluate to a list of odd numbers >= 3, but how?

Thanks, anyway. --

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