3 Apr
2012
3 Apr
'12
2:02 p.m.
On Mon, Apr 02, 2012 at 09:58:31PM +0100, felipe zapata wrote:
Hi.
I'm Following the book of Programming in haskell written by Graham Hutton. In Chapter number 8 there is a discussion about functional parsers and it is defined a functional Parser item and some basic parsers as follow
How is the Parser type defined? The problem may be that you need to make Parser a newtype, and write a Monad instance for it -- if Parser is defined as a type synonym, then there will be a default Monad instance used (the one for functions) but that is not the one you want. -Brent