[Haskell-beginners] Re: Function composition with more than 1 parameter

The lambdabot on #haskell has a plugin named "pointless" that can transform this into a definition that doesn't mention x and xs anymore. I think it will propose

howMany = (length .) . matches

And with

matches x xs = filter (x==) xs

matches x = filter (x==)

matches = filter . (==)

we have

howMany = (length .) . filter . (==)

howMany = curry (length . uncurry matches)

Thanks apfelmus, unfortunately, none of those suggested changes seem to work ! I get errors like :- Unresolved top-level overloading *** Binding : howMany2 *** Outstanding context : Eq b I'm using WinHugs - do you get them to work in some other environment ? Thanks ! :)