Re: [Haskell-begin] Alternating sequence

Hi Felipe, very nice simplification. Now I can even recognize the pattern used in the fibonacci number solution. Thanks, Dirk 2008/7/21 Felipe Lessa :

On Mon, Jul 21, 2008 at 11:21 AM, Bernie Pope wrote:

...

suffix = 5 : [ x + y | (x,y) <- zip suffix (cycle [2,4])] list = 2 : 3 : suffix

'suffix' can be simplified a bit by using zipWith:

suffix = 5 : zipWith (+) suffix (cycle [2,4])

Thanks,

-- Felipe.