Re: [Haskell-beginners] Selecting Arguments in Function to Feed Map

To actually give the example:

-- assuming that x and z are defined, and ys is the list map (\y -> f x y z) ys

On Mon, Sep 13, 2010 at 9:16 AM, Magnus Therning wrote:

On Mon, Sep 13, 2010 at 14:03, Lorenzo Isella wrote:

...

Dear All, Suppose you have the function

f x y z = x*y +z

and that you want to iterate it on a list z=[1,2,3,4], with x=4 and y=3

then you would do the following

map (f x y) z.

Now consider the case in which the list is given by y e.g.

y=[1,2,3,4], with x=4 and z=3.

How can you iterate f on y (i.e. its second argument) while keeping x and y fixed?

Using a lambda expression (anonymous function) or through clever use of flip.

/M

-- Magnus Therning (OpenPGP: 0xAB4DFBA4) magnus＠therning．org Jabber: magnus＠therning．org http://therning.org/magnus identi.ca|twitter: magthe _______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners

-- Alex R