
Sorry, I misunderstood your ruby. The Day datatype has an ordinal
instance for this purpose and also a convenient show instance in case
you wanted it.
import Data.Time.Calendar
import Data.Time.Format
import System.Locale
main =
let
(Just now) = (parseTime defaultTimeLocale "%F" "2011-07-11" :: Maybe Day)
(Just end) = (parseTime defaultTimeLocale "%F" "2011-07-15" :: Maybe Day)
in mapM_ print [now..end]
On Sat, Jul 9, 2011 at 1:14 PM, David McBride
import Data.Time.LocalTime import Data.Time.Format import System.Locale
now :: Maybe LocalTime -- Change this to get different types of values (days, etc). now = parseTime defaultTimeLocale "%F" "2011-07-11"
main = putStrLn $ case now of Nothing -> "Failed Parse" Just x -> (formatTime defaultTimeLocale "%F" x)
On Sat, Jul 9, 2011 at 12:33 PM, Rolf Hanson
wrote: Hi, I'm trying to iterate over a range of dates and print them out. Here's how I am doing it in Ruby:
'require 'date'
now = Date.parse('2011-07-11') end_date = Date.parse('2011-12-31')
(now..end_date).each do |d| # print out a date that looks like: # Monday, July 11, 2011 puts "#{d.strftime('%A, %B %d, %Y')}" end
I've been looking at the docs for Data.Time.Format and Data.Time.Calendar and am a bit puzzled at where to begin. Anyone have ideas? I've not found many (any?) examples of time and date manipulation in Haskell.
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