Re: [Haskell-beginners] Inverse trig functions

Seems like I was wrong then. I'll give it another go in the morning. Thanks to all, Adrian. On 20 Sep 2013 21:14, "Graham Gill" wrote:

Prelude> asin(1/sqrt(2)) * 180 / pi 45.0

asin is taking a ratio and returning an angle in radians, and I've converted it to degrees to show that clearly.

Graham

On 20/09/2013 7:52 AM, Adrian May wrote:

Apparently not. Those are 1/sin and 1/cos. I want to supply a ratio and get an angle.

On 20 September 2013 19:40, Martin Ruderer wrote:

...

Hello Adrian,

those would be called asin and acos.

Best regards, Martin

_______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners

_______________________________________________ Beginners mailing listBeginners@haskell.orghttp://www.haskell.org/mailman/listinfo/beginners

_______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners