 
            
            
            
            
                1 Jan
                
                    2009
                
            
            
                1 Jan
                
                '09
                
            
            
            
        
    
                2:35 a.m.
            
        On 2009 Jan 1, at 2:32, Max.cs wrote:
data Tree a = a | Branch (Tree a) (Tree a) deriving Show
but it seems not accpetable in haskell ?
You need a constructor in both legs of the type:
data Tree a = Leaf a | Branch (Tree a) (Tree a) deriving Show
-- brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allbery@kf8nh.com system administrator [openafs,heimdal,too many hats] allbery@ece.cmu.edu electrical and computer engineering, carnegie mellon university KF8NH