j
k
j a
j l
s mp $ n - 1 parses as s mp (n - 1) s mp n - 1 parses as (s mp n) - 1
It should be s mp $ n - 1 parses as ($) (s mp) (n - 1) which evaluates to s mp (n - 1) The parsing goes this way because ($) has the lowers precedence. -- Regards Sumit Sahrawat
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