Re: [Haskell-beginners] Question on evaluating function compostion

Why did Haskell, however, not try to fully evaluate addition, like following? (liftM . (+)) 1 [2] ---> liftM ((+) 1 [2]) ---> error

Haskell functions only consume one argument, not two. The composed function is applied to the first argument, which is 1. That returns a new function, which is applied to the next argument, which is [2]. e