
You can use insertWith:
http://hackage.haskell.org/package/containers-0.5.6.3/docs/Data-Map-Strict.h...
E.g.:
let xs = [("Item0", ["a","b","c"]), ("Item1", ["x","y"])]
let m = Map.fromList xs
Map.insertWith (++) "Item0" ["d"] m
"d" is cons'ed from the left, so it shouldn't be too slow. I don't know why
insertWith has this type instead of:
Ord k => (b -> a -> a) -> k -> b -> Map k a -> Map k a
which would allow you to write Map.insertWith (:) "Item0" "d" m
Maybe you should report it.
--
Sylvain
2015-11-10 6:23 GMT+01:00 Dan Stromberg
These are some good leads.
I'll be adding values one at a time, and yes, my keys aren't necessarily unique.
Is there a way of cons'ing on the single values one at a time, that will avoid the slowness of ++ ?
Thanks.
On Mon, Nov 9, 2015 at 7:45 PM, Sylvain Henry
wrote: import qualified Data.Map as Map
-- if your keys are unique let xs = [("Item0", ["a","b","c"]), ("Item1", ["x","y"]), ("Item2", ["abc","def"])] Map.fromList xs
-- if you want to combine values for keys that are equal let xs = [("Item0", ["a","b","c"]), ("Item1", ["x","y"]), ("Item0", ["abc","def"])] Map.fromListWith (++) xs
-- Sylvain
2015-11-10 3:07 GMT+01:00 Dan Stromberg
: I'm spending a little time here and there to learn some Haskell. I'm coming from a chiefly Python/C/bash background.
I want to build a Data.Map where the keys are strings, and the values are lists of strings.
In Python, collections.defaultdict(list) makes this pretty straightforward. It gives a hash table ("dict") that has values that default to an empty list, since list() produces an empty list. More info here: https://docs.python.org/3/library/collections.html#collections.defaultdict
Is there an equivalent in Haskell?
Thanks!
-- Dan Stromberg
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-- Dan Stromberg
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