[Haskell-beginners] Why are the types of the result different?

29 Sep 2010


      testWhere1 = a
             where b = 1
                      a = b+1
...
testWhere1
 2
testWhere2 = a
             where b = 1
                      c = 1/(b - b)
                      a = b+1
...
testWhere2
 2.0
The same thing happens with let.

testLet1 = let a = b+1
                         b = 1
               in a
...
testLet1
2
testLet2 = let a = b+1
                   c = 1/(b - b)
                   b = 1
               in a
...
testLet2
2.0
-- Russ Abbott
______________________________________
  Professor, Computer Science
  California State University, Los Angeles

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  blog: http://russabbott.blogspot.com/
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