well,
selFn = map (\x -> (! x)) sel -- This is not necessarily the most elegant way to word it would return a list of functions, which, when applied to a list, return an element from it based on the index results = map ($ ml) selFn would solve your problem
alternatively (and more cleanly),
results = map (ml !) sel
On Fri, Sep 10, 2010 at 10:55 AM, Lorenzo Isella
Dear All, I know this must be a one-liner, but it am banging my head against the wall. I am trying my hands at list manipulation in Haskell and a lot of useful function are making my life easier but I cannot achieve something really simple. Let us say you have the lists ml and sel
ml=[23,44,55,8,98] and sel=[1,2] .
Now, I would like simply to get a new list whose entries are the elements of ml in position sel. In my case things might be a little more complicated because all the elements are Integer and not Int (I noticed that sometimes this means I have to resort to generic functions). Cheers
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