Re: [Haskell-beginners] Running a list of functions

Ozgur Akgun wrote:

Actually in this case sequence and sequence_ are identical. You have IO for m, and () for a, so:

sequence :: [IO ()] -> IO () sequence_ :: [IO ()] -> IO ()

No, compare the type signatures: sequence :: [IO ()] -> IO [()] sequence_ :: [IO ()] -> IO () In the former case you will receive a list of as many values of type () as there are actions. Greets, Ertugrul -- nightmare = unsafePerformIO (getWrongWife >>= sex) http://ertes.de/