K, so I have a function that I’m writing that takes a *string* and a *count* and prints the *string* to STDOUT *count* times: displayD :: IO () -> String -> Int displayD string count = do (count > 0) && hPutStr stdout string (count > 0) && displayD string (count - 1) However, when I try to compile the file, I get several errors; here’s a pastebin: http://pastebin.com/DEsuAvfz What I’m trying to do here is check to see if *count* is greater than 0, and then if it is, then I’d like to print *string* to STDOUT until *count* equals 0. I tried doing it via pattern matching, like so: displayD string (count > 0) = do But I haven’t seen any examples of how to do pattern matching in functions using *do*, that is *IO*, so I’m unsure if the above is even anywhere near correct. Still very uncomfortable with declaring function types: I have a hard time figuring out which type is returned and what type is expected as an arg. My initial guess is that the *first* type specified is the one returned, but I’m not sure. -- Alexej Magura Sent with Airmail