On 20 Mar 2009, at 12:05, 7stud wrote:
On p. 76 of RWH, it says:
"If a function or constructor takes two or more arguments, we have the option of using it in infix form, where we place it between its first and second arguments."
Here is my code:
func2 x y = x + y
func3 x y z = x + y + z
Here are the results:
*Main> func2 10 20 30 *Main> 10 `func2` 20 30 *Main> func3 10 20 30 60 *Main> 10 `func3` 20 30
<interactive>:1:11: No instance for (Num (t1 -> t)) arising from the literal `20' at <interactive>:1:11-15 Possible fix: add an instance declaration for (Num (t1 -> t)) In the second argument of `func3', namely `20 30' In the expression: 10 `func3` 20 30 In the definition of `it': it = 10 `func3` 20 30
How do you get a function to work using infix notation when it has 3 arguments?
Prelude> (10 `func3` 20) 30 60 Bob