[Haskell-beginners] Bit arithmetic in Haskell

9 Dec 2008

      Hello,

I'm trying to do some bit arithmetic. Here's the function:
...
import Data.Bits
import Data.Word
g :: Word32 -> [Word32]
g x = [(x `shiftR` 24) .&. 0xFF,
       (x `shiftR` 16) .&. 0xFF,
       (x `shiftR` 8) .&. 0xFF,
       x .&. 0xFF]
This function should give bytes for the given number, like this:

g 255 -> [0,0,0,255]
g 256 -> [0,0,1,255]
g 65535 -> [0,0,255,255]

In reality, I get very strange answers.

Can anybody help me please?

Regards,
Artyom Shalkhakov.