Hi, a friend of mine wanted to write function (in Perl) that creates all tuples of length 3 of the elements of a given list, e.g. [(0,0,0),(0,0,1),(0,0,2),...,(5,5,5)] for the list [0..5]. Trying to get better at Haskell, I wrote a small function using the list monad for this (tuples replaced with lists) all3 ls = do a <- ls b <- ls c <- ls return [a,b,c] Now I want to make it capable to create all combinations of length n instead of fixed length 3 (that's why list instead of tuple), but I don't really see how. As the do notation translates to ls >>= \a -> etc. I thought it should be possible to have some sort of "foldr (>>=)" over a list of length n, but I can't figure out how to collect the variable number of results in a list for the "return". Any hints for that? best regards Matthias -- __________________________________________________________ ___ __ __ Dipl. Inf. Matthias Guedemann / __\/ _\ /__\ Computer Systems in Engineering / / \ \ /_\ Otto-von-Guericke Universitaet Magdeburg / /___ _\ \//__ Tel.: 0391 / 67-19359 \____/ \__/\__/ __________________________________________________________