Re: [Haskell-beginners] A simple function V2

On Fri, Aug 31, 2012 at 04:15:38PM +0200, Ertugrul Söylemez wrote:

Brent Yorgey wrote:

...

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*intercalate :: (Eq t) => [t] -> [t] -> [t]* *intercalate (x:xs) (y:ys)* * | xt == [] = []* * | yt == [] = []* * | otherwise = x : y : intercalate xs ys* * where xt=(x:xs)* * yt=(y:ys)*

I should also point out that the tests xt == [] and yt == [] will never be true! That is because xt is defined to be (x:xs) and yt is (y:ys).

That's actually not true. See his 'where' clause at the bottom.

That's exactly what I was looking at. Can you clarify what you mean? Which part of what I said is not true? -Brent