Re: [Haskell-beginners] putting together monadic actions

Hi, You can easily write your own:

import Control.Monad import Data.List let foo = flip (foldl' (>=>) return) :t foo foo :: (Foldable t, Monad m) => b -> t (b -> m b) -> m b let g x = return (x*2) foo 3 [g,g,g] 24

-Sylvain On 24/08/2016 03:00, Dennis Raddle wrote:

Is there a function foo that does

foo :: a -> [a -> m a] -> a

So

foo 3 [x,x,x] = return 3 >>= x >>= x >>= x

I don't think replicateM and sequence do this. At least I can't figure it out.

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