Hi William, I would also strongly success not to make the detour using read and show. Keep things simple. Here is my suggestion: toDigit x = case f x of (0,b) -> [b] (a,b) -> toDigit a ++ [b] f = \x -> (x `quot` 10, x `mod` 10) Best, Thomas William Gilbert wrote:
I am trying to write a function that will covert either an integer or an int into a list containing its digits.
ex. toIntegralList 123 -> [1,2,3]
I have written the following definition that tries to use read to generically cast a string value to an Integral type that is the same as the Integral passed in:
toIntegralList :: (Integral a) => a -> [a] toIntegralList x = map (\c -> read [c] :: a) (show x)
I understand it would be very simple to just create two functions, one that converts an Int and one that converts an Integer, however I was wondering if there were any way to accomplish what I am trying to do here.
Thanks In Advance, Bryan _______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners