Re: [Haskell-beginners] Re: Apparent bug

A few answers back, Matthew Coolbeth wrote, (show v) where v is of type Test will evaluate to (showPrec v), and that (showPrec v) will evaluate to (show v). It should be clear that this is a cyclic evaluation that will not terminate. Presumably that was intentional. But why was that necessary? It seems like strange coding. Furthermore, why isn't instance Show Test interpreted to mean data Test = Test deriving (Show) * -- Russ * On Tue, Nov 16, 2010 at 10:27 AM, Tobias Brandt wrote:

On 16 November 2010 19:17, Edward Z. Yang wrote:

...

It seems to me that there is a possibility we could reify some information that is traditionally specified in the documentation: that is, what functions must be defined by a minimal instance, which could then give GHC enough information to give meaningful warnings if not all functions for a minimal instance are proviced.

One could use a compiler pragma the defines possible sets of minimal definitions, e.g. {-# MINIMAL_DEF Num ((+),(*),abs,signum,fromInteger,(-)), ((+),(*),abs,signum,fromInteger,negate) #-}

one could even add logical notation, like: {-# MINIMAL_DEF Num ((+), (*), abs, signum, fromInteger, (-) || negate) #-}