Re: [Haskell-beginners] Count with Writer asynchronously

Hello, Michael! This answers to my question completely, thank you so much! But looking at this code, I thought: how is it right to wrap/unwrap write monad? In languages like C or Python we can pass input/output argument (`int*` in C or `[0]` in Python) and use it as some accumulator. But here writer monad is not using as accumulator, accumulating (summation) happens in `mconcat`, right? It's using only as output value, i.e. place to "yield" result. I mean `w` is 0, each call of `runIt` sets there 1, after all calls we calculate sum of this 1's. And instead of `censor (+1) w` I can do `tell 1` only. It means that `runIt` can return not `IO ()` but `IO Int` and results of all `runIt`'s asynchnronously gotten values can be accumulated with `mconcat` without using of writer monad. Am I right, writer monad here is not accumulator but only output value (like output arguments in C/C++/IDL/etc)? How is this a typical solution in Haskell - to use writer monad with wrap/unwrap multiple times, only to save output value? On Tue, 25 Jul 2017 12:31:56 +0300 Michael Snoyman wrote:

Firstly, a direct answer to your question: use mconcat.

main :: IO () main = do let l = [1,2,3,4] w = writer ((), 0) :: WriterT (Sum Int) IO () z <- sequence (map (A.async . runWriterT . runIt w) l) >>= mapM A.wait print $ snd $ mconcat z

Under the surface, WriterT is using mappend to combine the `Sum` values anyway, so it's natural is `mconcat` (the version of mappend that applies to list) to get the same result. Now some possible improvements.

You're not actually using the return value from the `runIt` call, just the writer value. There's a function called `execWriter` for this:

z <- sequence (map (A.async . execWriterT . runIt w) l) >>= mapM A.wait print $ mconcat z

Next, the combination of map and sequence can be written as traverse:

z <- traverse (A.async . execWriterT . runIt w) l >>= mapM A.wait

But the async library is cool enough that it provides a function called mapConcurrently that deals with the async/wait dance for you:

main :: IO () main = do let l = [1,2,3,4] w = writer ((), 0) :: WriterT (Sum Int) IO () z <- A.mapConcurrently (execWriterT . runIt w) l print $ mconcat z

One final note: usage of `print` like this in a concurrent context can run into interleaved output if you have the wrong buffer mode turned out, leading to output like this:

2 3 41

This is especially common when using runghc or ghci. You can either change the buffering mode or use a different output function like sayShow (from the say package, which I wrote):

module Main where

import qualified Control.Concurrent.Async as A import Control.Monad.Trans.Writer import Data.Monoid import Say

runIt :: (Show a, Num a) => WriterT (Sum a) IO () -> a -> WriterT (Sum a) IO () runIt w x = do censor (+1) w -- emulates conditional count of something sayShow x

main :: IO () main = do let l = [1,2,3,4] w = writer ((), 0) :: WriterT (Sum Int) IO () z <- A.mapConcurrently (execWriterT . runIt w) l sayShow $ mconcat z

On Tue, Jul 25, 2017 at 11:36 AM, Baa wrote:

...

Hello, Dear List!

There is package `async` (https://hackage.haskell.org/package/async-2.1.1.1/docs/ Control-Concurrent-Async.html).

Before, I had:

import qualified Control.Concurent.Async as A ... runIt :: ... -> IO () ... sequence [A.async $ runIt ...] >>= mapM_ A.wait

But now I want to count something inside `runIt`. I will use `Writer` monad for it (sure, it can be `State` also, not in principle to me). To do it synchronously, I done:

module Main where

import Control.Monad.Trans.Writer import Control.Monad.IO.Class import Data.Monoid

runIt :: (Show a, Num a) => WriterT (Sum a) IO () -> a -> WriterT (Sum a) IO () runIt w x = do censor (+1) w -- emulates conditional count of something liftIO $ print x

main = do let l = [1,2,3,4] w = writer ((), 0) :: WriterT (Sum Int) IO () z <- runWriterT $ sequence [runIt w i | i <- l] print $ snd z

but now my `runIt` changes it's signature:

runIt :: Num a => WriterT (Sum a) IO () -> ... -> WriterT (Sum a) IO () ... sequence [A.async $ runIt ...] >>= mapM_ A.wait ^^^^^^^^^^^ ` ERROR is here!

I get the error because `async`::IO () -> IO (A.Async ()) but I'm trying to pass it `WriterT (Sum a) IO ()`!

To fix it I added `runWriterT` there:

res <- sequence [A.async $ runWriterT (runIt ...) ...] >>= mapM A.wait

but now I will get list of counters, not one (res::[((), Sum Int)])!

How to solve this problem: to run several actions asyncronously and to count something inside the action with `Writer` monad?

=== Best regards, Paul _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners