[Haskell-beginners] Disjunction

I recently was writing code long these lines. f x = p1 x || p2 x || ... || pn x I would have liked to write that in pointfree form but couldn't find a library function to do it. I created this. disj :: [a -> Bool] -> a -> Bool disj ps = (\x -> or $ map ($x) ps) disj2 p1 p2 = disj [p1, p2] disj3 p1 p2 p3 = disj [p1, p2] disj4 p1 p2 p3 p4 = disj [p1, p2] ... With that I can write my function as follows. f = disj pi p2 p3 ... pn Is there a standard way to do this? * -- Russ*