25 Nov
2010
25 Nov
'10
6:14 a.m.
I don't know whether this is related or not, but I have the following somewhere in my code: -- the following is apparently eqivalent to (\ i -> foo (bar i) i). -- pointfree suggests so. i don't understand why. (foo =<< bar) Is this a similar situation? -- Ozgur Akgun