Re: [Haskell-beginners] why is there no typeclass common to all containers?

Map is (you map over the values, not the keys).

On Wed, Jun 1, 2016 at 1:14 AM Tony Morris wrote:

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Map and Set are not.

On 01/06/2016 8:57 AM, "Jeffrey Brown" wrote:

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In Haskell typeclasses are based on what you want to do with something.

If, for instance, you want to be able to map over a container, you can make it an instance of class Functor -- which all the standard containers (List, Map, Set, Tree, Maybe ...) already are.

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On Tue, May 31, 2016 at 3:26 PM, Silent Leaf wrote:

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In fact it all comes down to trying to add partially a feature absent

from the Haskell language, which is the ability to distinguish values both on name *and* on type --thus allowing two variables of the same name if

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Honestly i don't see the drawback of that name system, but i guess

map and set are not what? I didn't get it. That's cool, I'll look into it! As for why Haskell doesn't allow natural overloading of any function name merely by choosing another name, does anyone know? Le mercredi 1 juin 2016, Alex Rozenshteyn a écrit : they have different types. there must be one otherwise it'd have been chosen by default instead of the typeblind current name system.

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Le mercredi 1 juin 2016, Silent Leaf a écrit :

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All in the title. I haven't used them much, but I saw Map or Vector

types were forcing the user to use qualified functions unless you want nameclash with the more basic, typically list-oriented functions.

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So, why not have a massive, general purpose interface so the type only can separate between containers --which would allow for cross-container polymorphism, i suppose, more easily, even though it's not necessarily the most widespread need. So, do i miss something? Is there in fact a class of that kind? If so why not? Thanks in advance! :)

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