Re: [Haskell-beginners] function defenition. Do I understand it right?

On 12.07.2011 11:44, Roelof Wobben wrote:

So I thought this would work . halve (xs) | length xs == 0 = []

This returns a list

| length xs `mod`2 == 0 = (take n xs, drop n xs) | otherwise = (take (n+1) xs, drop (n+1) xs)

These return a pair of two lists each.

where n = length xs `div`2

You probably want to return a pair of empty lists in the first case, too. HTH, Thomas