
25 Nov
2008
25 Nov
'08
1:27 a.m.
On 2008 Nov 24, at 12:12, Brent Yorgey wrote:
In general, the point is that there is already a 'whitespace operator' in Haskell corresponding to function application. So it would be ambiguous for whitespace to also indicate separation of list elements.
The other generality I'd add is that Haskell isn't Scheme, and it's best to get used to it. (Although there is Liskell if you're feeling weird.) -- brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allbery@kf8nh.com system administrator [openafs,heimdal,too many hats] allbery@ece.cmu.edu electrical and computer engineering, carnegie mellon university KF8NH