Re: [Haskell-beginners] Parse string with optional entries [Parsec]

Read up on the sepBy combinator. parse (sepBy (many digit) (char ',')) "" "123,321,,2321" Right ["123","321","","2321"] On Mon, Aug 8, 2011 at 7:53 AM, wrote:

Hi,

I have something similar to the CSV-Parser in RWH, chapter 16. The problem are the possible empty cells, i.e. consecutive '\t'-Characters.

-----Original Message----- From: Antoine Latter [mailto:aslatter@gmail.com] Sent: Monday, August 08, 2011 1:44 PM To: Lukasser Stefan (IFAT IMM PSD D TEC / EE) Cc: beginners@haskell.org Subject: Re: [Haskell-beginners] Parse string with optional entries [Parsec]

On Mon, Aug 8, 2011 at 6:39 AM,   wrote:

...

Hi all,

I'm trying to parse a string in one of the following forms using Parsec:

"1\t1\t123\t456" -> desired output: [Just 1, Just 1, Just 123, Just 456]

or

"1\t\1\t\t456"  -> desired output: [Just 1, Just 1, Nothing, Just 456]

i.e., the input is a list of numbers, separated by '\t' characters, with the possibility of missing entries. I'm having troubles with the backtracking in case of missing numbers. Can anybody give me a hint?

What do you have so far?

...

Thanks in advance, Stefan

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