[Haskell-beginners] Re: Offside rule for function arguments?

The indentation on the second line would generate a parse error, the same as it does now. On 23/08/2010 12:32, Jonas Almström Duregård wrote:

Maybe because of this:

function 0 = 0 where fun 1 = 1 2 = 2

The last declaration (2=2) can define either fun or function. I'm not saying this is a major problem, but there may be other problems like these.

/J

On 23 August 2010 11:15, Brent Yorgey mailto:byorgey@seas.upenn.edu> wrote:

...

On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:

...

Why doesn't Haskell allow something like this?

fac 0 = 0 1 = 1 x = x * fac (x-1)

This would be clearer than repeating the function name each time, and follow the same pattern as guards and case.

Good question. I don't know of any particular reason.

-Brent