Re: [Haskell-beginners] foldr with short circuit and accumulator

Hi, Implementing a short-circuiting fold was already discussed in the haskell-cafe mailing list. https://mail.haskell.org/pipermail/haskell-cafe/2007-April/024171.html On Tue, Feb 2, 2016 at 4:15 PM, Chul-Woong Yang wrote:

Hi, all.

Can it be possible to do fold with short circuit and accumulator both? For example, can we find an element which is same value to adjacent one?

findAdjacent [1,2..n, n, n+1, n+2.......] => n \__very long__/

Though there can be many ways to do it, Can we do it with fold[r|l]?

I'll be happy to receive any comments.

Chul-Woong _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners