Brent, Thank you for the responses. I appreciate it. Bummer about there not being some kind of built-in/generic shortcut. Bryce On 02/22/2013 12:14 PM, Brent Yorgey wrote:
On Fri, Feb 22, 2013 at 02:07:43PM -0500, Brent Yorgey wrote:
On Fri, Feb 22, 2013 at 10:43:32AM -0800, Bryce Verdier wrote:
Lets say I have a data type like so:
data IpAddress = IpAddress {$ o1 :: !Int,$ o2 :: !Int,$ o3 :: !Int,$ o4 :: !Int$ } deriving (Show)$
which you can create by doing: IpAddress 192 168 1 1
Is there a way to do the same thing with the input data in a list? Like: IpAddress [192,168,1,1]
or using some operator (or combination of operators):Like (I'm guessing (<????>) isn't in use): IpAddress <????> [192,168,1,1] No, there isn't. But you can make a function
ipAddress :: [Int] -> IpAddress ipAddress [a,b,c,d] = IpAddress a b c d For that matter you can define the operator (<????>) yourself:
(<????>) :: (a -> a -> a -> a -> b) -> [a] -> b f <????> [a,b,c,d] = f a b c d
Not sure how useful it is though.
-Brent
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