Re: [Haskell-beginners] '/' instead use 'DIV'. why?

It might help to imagine if you flip your arguments: length [23, 34, 45] / 6 :: Int How do you represent 3/6 as an Int?

El 17 abr 2020, a las 03:19, Alexander Chen escribió:

Hi,

Prelude> :t (/) (/) :: Fractional a => a -> a -> a

Prelude> :t div div :: Integral a => a -> a -> a

Prelude> 6 / length [23,34,45] error

Prelude> 6 / 3 2.0

Could somebody explain to me why this is?

thanks,

Alexander Chen

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