[Haskell-beginners] Re: Haskell Generic Function Question

Jeff Wheeler wrote:

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f = \x -> (x `quot` 10, x `mod` 10)

Your function f is almost the same as divMod in Prelude. Also, using a lambda function seems odd; this is simpler:

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f x = (x `quot` 10, x `mod` 10)

Hmm, simplicity. f = (`quot` 10) &&& (`mod` 10) SCNR. Greets, Ertugrul. -- nightmare = unsafePerformIO (getWrongWife >>= sex) http://blog.ertes.de/