Re: [Haskell-beginners] No instance for (Show a)

31 Jul 2011

      On Sunday 31 July 2011, 11:19:36, Ovidiu Deac wrote:
...
For some reason ghc complains about not being able to call show on an
Integer (?!?!?)
No, it complains about not being able to call show on a value of arbitrary 
type. Your

instance Show (Stack a) where

says you can show stacks of arbitrary type, so nothing can be assumed about 
the element type, but in the implementation you try to call show on the top 
element.
To make it work, you have to tell GHC that the elements can be shown,

instance (Show a) => Show (Stack a) where
   -- what you have

would work. The "(Show a) =>" part says roughly "if elements of the stack 
can be shown, then the stack can be shown".
...
Please enlighten me!
ovidiu
This is the hspec:
    it "shows one element"
        ( show (push 1 EmptyStack) ≡ "Stack(1)")
...this is the code:
data Stack a =
    EmptyStack |
    StackEntry a (Stack a)
    deriving(Eq)
instance Show (Stack a) where
    show s =
        "Stack(" ⊕ (showImpl s) ⊕ ")"
        where
            showImpl EmptyStack = ""
            showImpl (StackEntry x _) = show x
...and this is the error:
src/Stack.hs:12:22:
    No instance for (Show a)
      arising from a use of `showImpl'
    In the first argument of `(++)', namely `(showImpl s)'
    In the second argument of `(++)', namely `(showImpl s) ++ ")"'
    In the expression: "Stack(" ++ (showImpl s) ++ ")"

Re: [Haskell-beginners] No instance for (Show a)

Daniel Fischer